Question

I will mark him brainliest who answer correct .

Answer 1

$\huge{\mathcal{\underline{\green{SOLUTION}}}} </p><p>$

${ (\frac{5}{7}) }^{(x - 1)} = {( \frac{7}{5} )}^{(x - 5)}$

$\implies \: { ( {(\frac{7}{5})}^{ - 1} ) }^{(x - 1)} = {( \frac{7}{5} )}^{(x - 5)}$

$\implies \: { (\frac{7}{5}) }^{( - x + 1)} = {( \frac{7}{5} )}^{(x - 5)}$

Using the law

${a}^{m} = {a}^{n} \: \: gives \: \: m = n$ of indices we get

$- x + 1 = x - 5$

$\implies \: 2x = 6$

$\implies \: x = 3$

$</p><p></p><p>\displaystyle\textcolor{red}{Please \: Mark \: it \: Brainliest}$

Answer 2

Answer:

hope it will help you

Be Brainly