Question

I will mark u as brainlist.......................... Find the real numbers of x and y if(x-1)i+(y+1)=(1+i)(4-3i)

Answer 1

z=x−2 i1+i=(x−2 i1 +i)(1− i1−i)=x−ix−2i +2i 21−i2 =x−i(x+2)−21+1 [As i2=−1]⇒(x−2)−i(x+2)2=x−22−i(x+22)As z is purely imaginary, hence x−22=0⇒x−2=0⇒x=2 (Answer)z=x-2i1+i=x-2 i1 +i1 -i1-i=x-ix-2 i+2i 21-i2=x-ix+2-21+1 As i2=-1⇒x-2-ix+22=x-22-ix+22 As z is purely imaginary, hence x-22=0⇒x-2=0⇒x=2 Answer