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If a and ß are the zeroes of a quadratic polynomial such that a + ß = 0 and a- ß = 8. Find the quadratic polynomial having a and ß as it's zeroes.
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Answer:
x² - 16
Step-by-step explanation:
Given that α and β are the zeros of a quadratic polynomial such that
α + β = 0
α - β = 8
----------------
2α = 8
α = 4
Substitute α = 4 in (1), we get
α + β = 0
⇒ 4 + β = 0
⇒ β = -4
The value of α and β are 4 and -4 respectively.
If α and β are the zeros of a quadratic polynomial, the polynomial is in the form of
P(x) = x² - (α + β)x + αβ
= x² - 0 - 16
= x² - 16
Therefore, the required polynomial is x² - 16
Hope it helps!
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