Question

i³+i³⁹+i¹²¹+i²⁰²¹
pls answer it​

Answer 1

Answer of i^3+i^39+i^121+i^2021 is -4i

Answer 2

Answer:

i³ + i³⁹ + i¹²¹ + i²⁰²¹

= i²(i) + i³⁶ × i³ + i¹²⁰ × i¹ + i²⁰²⁰ ×i¹

= -i + i³ +i + i

= -i - i +2i

= -2i +2i = 0

Step-by-step explanation:

formula used i⁴ⁿ = 0 , where n is any I natural numbers

and i = √-1

so,

i² = -1

$.$