Question

Identify which atoms are oxidized and which are reduced in the following redox reactions. mention oxidants and reductants
H202+Clo7---->ClO2+O2​

Answer 1

Answer:

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Explanation:



ANSWER

The oxidation number of chlorine decreases from +7 to +3 and the oxidation number of Oincreases from -1 to zero. Thus, Cl2O7 is oxidizing agent and H2O2 is the reducing agent.

Ion electron method:

The oxidation half equation is 

H2O2(aq)→O2(g)

To balance oxidation number, 2 electrons are added.

H2O2(aq)→O2(g)+2e−

2 hydroxide ions are added to balance the charge.

H2O2(aq)+2OH−→O2(g)+2e−

2 water molecules are added to balance the O atoms.

H2O2(aq)+2OH−→O2(g)+2H2O(aq)+2e−

The reduction half reaction is Cl2O7→ClO2−(aq)

The Cl atoms are balanced

Cl2O7→ClO2−(aq)

8 electrons are added to balance the oxidation number.

Cl2O7+8e−→