Question

Identify Z in the following series
C₂H₅I □(→┴Alc. KOH ) X □(→┴Br₂ ) Y □(→┴KCN ) Z
(a) CH₃CH₂CN (b) NCCH₂–CH₂CN
(c) BrCH₂–CH₂CN (d) BrCH=CHCN

Answer 1

Option (C)

Explanation:

$C_2H_5I\xrightarrow[KOH]{Alcoholic} C_2H_2$

Alcoholic  KOH makes dabble bond.

$H_2C=CH_2 \xrightarrow[]{Br_2} BrH_2C-CH_2Br$

Br₂ breaks the dabble bond.

$BrH_2C-CH_2Br\xrightarrow[]{KCN} BrH_2C-CH_2CN +KBr$

Z is $BrH_2C-CH_2CN$