identity the nature of root of x^2-3x+4root2=0
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The roots are imaginary, there are no real roots.
Step-by-step explanation:
We've been given a quadratic equation, and we're asked to find the nature of the roots.
The equation is x² - 3x + 4√2, where;
- a = co-efficient of x² = 1
- b = co-efficient of x = -3
- c = constant term = 4√2
We know that the nature of the roots of a quadratic equation is given by its discriminant (D).
Discriminant (D) = b² - 4ac
1) If D > 0
- Nature of roots: Roots are real, both the roots are distinct. (Unequal)
2) If D = 0
- Nature of the roots: Roots are real, both the roots are equal.
3) If D < 0
- Nature of the roots: Roots are imaginary, there are no real roots.
For the quadratic equation x² - 3x + 4√2;
⇒ Discriminant (D) = b² - 4ac
⇒ Discriminant (D) = (-3)² - 4(1)(4√2)
⇒ Discriminant (D) = 9 - 16√2
⇒ Discriminant (D) = 9 - 16(1.414)
⇒ Discriminant (D) = 9 - 22.624
⇒ Discriminant (D) = -13.6274 (approx)
Here, D = -13.6274, meaning D < 0.
∴ The nature of the roots are imaginary, there are no real roots.
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