Question

if (0,0),(2,0),(0,3),are vertices of a triangle then find its area​

Answer 1

Answer:

Example: What is the area of the ∆ABC whose vertices are A(1, 2), B(4, 2) and C(3, 5)? A = (1/2) [-3 + 12]= 9/2 square units. Therefore, the area of a triangle ABC is 9/2 square units

Answer 2

Answer:

we have area formula of triangle,

              Δ = 1/2 [ x₁ ( y₂ - y₃ ) + x₂ ( y₃ - y₁ ) + x₃ ( y₁ - y₂ ) ]

 (x₁ , y₁) = ( 0 , 0 )  , ( x₂ , y₂ ) = ( 2 , 0 ) , ( x₃ , y₃ ) = ( 0 , 3 )

              Δ = 1/2 [ 0 ( 0 - 3 ) + 2 ( 3 - 0 ) + 0 ( 0 - 3 )

              Δ = 1/2 * 6

              Δ = 3 unit² (Ans.)