Question

if 0 and 1 are the zero of the polynomial f(x)=2x^3-3x^2+ax+b find a and b?​

Answer 1

Answer:

b=0 and a=1

Step-by-step explanation:

2*(0)^3-3*(0)^2+a*0+b =0

0=0-0-0+b

so,b=0

and also

2*(1)^3-3*(1)^2+a*1+b=0

0=2-3+a+b

1=a+0

so, a=1

Answer 2

Question:

if 0 and 1 are the zero of the polynomial f(x)=2x^3-3x^2+ax+b find a and b?

Answer:

a= 1,

b= 0.

Step-by-step explanation:

we have given value,

f(0) = 2x³-3x²+ax+b

= 2(0)³-3(1)²+a(0)+b

= 0+0+0+b.

= b. ----------(1)

again,

f(1)= 2x³-3x²+ax+b.

= 2(1)³-3(1)²+a(1)+b

= 2-3+a+b

= -1+a+b. --------(2)

Form equation, 1 and 2 we get,

b=-1+a+b.

=>a= 1.

and, b= 0.

Some information,

f(x)= 2x²-2x+1.

it's means when putting, any value in the place of x we got then x is the zero of f(x)