Question

if Alfa ,beta ,GA are zeroes of x^+3x^-x-3then find 1÷alfa+1+beta+1÷gama​

Answer 1

Answer:

=-1/3

Step-by-step explanation:

we have equation,

x³+3x²-x-3.

we know formula for zeros,

$\alpha +\beta +\gamma = \frac{-b}{a}$

$\alpha\times \beta \times \gamma=\frac{-d}{a}$

$\alpha\beta +\beta\gamma +\gamma \alpha=\frac{c}{a}$

A/Q,

=>1/alpha + 1/beta+ 1/ gamma = alpha beta +beta gamma + gamma alpha /alpha beta gamma

=>-1/3.

Answer 2

Answer:

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