Question

If 0 be the centre of the circle , Find the value of x in the circle ​​

Answer 1

Answer:

hope it helps

Step-by-step explanation:

(i) ∠ACB=∠ADB (Angles in the same segment of a circle)

But ∠ADB=x

o

⇒∠ABC=x

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Now in ΔABC

∠CAB+∠ABC+∠ACB=180

o

⇒40

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+90

0

+x

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=180

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(AC is the diameter)

⇒130

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+x

o

=180

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⇒x

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=180

0

−130

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=50

o