if 1\a, 1\b, 1\c are in arthemetic progression, then (1\a + 1\b - 1\c)*(1\b + 1\c -1\a)=?
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-1\a^2 +1\b^2-1\c^2+1\ac
anjana3110:
answer is 4\ac -3/b^2
thank you for answering
welcome
can you please solve and show
i don't know how to solve
my teacher said that answer
oh
Answered by
2
_1/w^2+1/b^2-1/c^2+1/ac
answer is 4\ac -1\b^2
but thank you for answering
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