If 1 and 3 are two zeroes of a polynomial x4 + x3 – 11x2 – 9x + 18, then find the zeroes of the polynomial.
JessicaMalik:
You can divide the given equation with x2-4x+3 and then the quotient that you will get,do middle term splitting and u will get two other zeroes
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zeros are x -1 and x-3
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heyyyyyyyyyyyyy friendddddddddd...
=>1 and 3 are the zeroes of p(x)=x4+x3+11x2-9x+18
=>x=1 and x=3 are the zeroes of p(x)
=>x-1=0 and x-3=0 are the zeroes of p(x)
=>(x-1) and (x-3) are the factors of p(x)
=>(x-1)(x-3) is a factor of p(x)
=>x(x-4)+ 1(x-3)is a factor of p(x)
=>x2-4x+ x -3 is a factor of p(x)
=>x2 -3x -3 is a factor of p(x)
HALF IS IN THE ATTACHMENT ABOVE...
HOPE IT HELPS YOU
=>1 and 3 are the zeroes of p(x)=x4+x3+11x2-9x+18
=>x=1 and x=3 are the zeroes of p(x)
=>x-1=0 and x-3=0 are the zeroes of p(x)
=>(x-1) and (x-3) are the factors of p(x)
=>(x-1)(x-3) is a factor of p(x)
=>x(x-4)+ 1(x-3)is a factor of p(x)
=>x2-4x+ x -3 is a factor of p(x)
=>x2 -3x -3 is a factor of p(x)
HALF IS IN THE ATTACHMENT ABOVE...
HOPE IT HELPS YOU
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