if 1 by 2 is a root of the equation X square + X - 1 by 4 equal to zero then the value of k
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p(x) = x² + kx -(1/4) =0
p(1/2) = (1/2)²+ k(1/2) - (1/4) = 0
= (1/4) + (k/2) -1/4 = 0
= k/2 = 0
= k =0
p(1/2) = (1/2)²+ k(1/2) - (1/4) = 0
= (1/4) + (k/2) -1/4 = 0
= k/2 = 0
= k =0
Christophersingh:
The value of k = 2
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