if 1 is a root of the equation a y square + Y + 3 = 0 and y square + Y + b = 0 then the value of a b is
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Step-by-step explanation:
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Step-by-step explanation:
If 1 is the root of the given equations then it would satisfy the conditions ;
a(1)^2+a(1)+3 = 0
2a = -3
a = -3/2
(1)^2+(1)+b =0
2 + b = 0
b = -2
ab = (-3/2)×-2
= 3
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