Question

prove that
(cosec + cot)² = sec+1 / sec-1​

Answer 1

Answer:

Step-by-step explanation:

Taking LHS =

(Cosec + cot)2

(1/sin +cos/sin)2

(1 +cos/sin)2

(1+cos)2/sin2

=Both square are cut by each other .so=

1/sin + cos/sin

Cosec + cot

Taking rhs =

Rationalising denominator

Sec +1 /sec -1

Sec+1 *sec+1/sec-1*sec+1

(Sec+1)2/sec2-1

(Sec+1)2/tan2

Both square are cut by each other

Sec/tan +1/tan

Cosec + cot = cosec + cot

Hence proved

Thanks