Question

If 1 is a zero of the polynomial p(x)=ax^2 -3(a-1)-1, then find the value of a

Answer 1

Answer:

please refer to the attachment

I hope it would help you

thank you

Answer 2

p(x)=ax^2-3(a-1)-1

p(1)=a(1)^2-3a+3-1

0=a-3a+2( since 1 is a zero of the polynomial)

-2=-2a

2=2a

2/2=a

a=1