If -1<x<1 then how 0<x^2 <1 exist? Prove it. Have anyone caliber to solve it?
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the statement is not fully correct. if I take a positive integer then only it will be correct. if 0 then 0=x^2<1
the statement is not fully correct. if I take a positive integer then only it will be correct. if 0 then 0=x^2<1
Answered by
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Hey there!!
If -1<x<1 given,
But we know that x²>0 can't be negative because even powers are always positive
So thats why : 0<x²<1
Wr can't take -1 in the domain of x² because x² is always positive
____________________________________
Hope it will help u
If -1<x<1 given,
But we know that x²>0 can't be negative because even powers are always positive
So thats why : 0<x²<1
Wr can't take -1 in the domain of x² because x² is always positive
____________________________________
Hope it will help u
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