Question

If 1/x+2/y=20 & 3/x+3/y=20,then 1/x+1/y =-----​

Answer 1

Answer:

1/X +2/y=20

y + 2x = 20xy....(1)

3/x +3/y =20

3y+3x=20xy.....(2)

(1) =(2)

y+2x= 3y+3x

X=2y

then put

1/X+1/y=

Answer 2

The value of $\dfrac{1}{x} +\dfrac{1}{y}$ is equal to $\dfrac{20}{3}$.

Step-by-step explanation:

We have,

$\dfrac{1}{x} +\dfrac{2}{y} = 20$                                   .......... (1)

and

$\dfrac{3}{x} +\dfrac{3}{y} = 20$                                 .......... (2)

To find, the value of $\dfrac{1}{x} +\dfrac{1}{y}$  = ?

Equation (2) re-written as,

$\dfrac{3}{x} +\dfrac{3}{y} = 20$    

Dividing both sides by 3, we get

$\dfrac{1}{3} (\dfrac{3}{x} +\dfrac{3}{y}) =\dfrac{20}{3}$    

⇒ $\dfrac{1}{x} +\dfrac{1}{y}$ $=\dfrac{20}{3}$

∴ The value of $\dfrac{1}{x} +\dfrac{1}{y}$  $=\dfrac{20}{3}$

Thus, the value of $\dfrac{1}{x} +\dfrac{1}{y}$ is equal to $\dfrac{20}{3}$.