If 100! divisible by 3n then find the maximum value of n
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Answered by
10
Find the maximum power of 3 in 157!
Which is [157/3]+[157/9]......=52+17+5+1=75
Now maximum power of 9 in it=[75/2]=37
So n can be any integer from 0 to 37
If we are considering division only by positive integers
Which is [157/3]+[157/9]......=52+17+5+1=75
Now maximum power of 9 in it=[75/2]=37
So n can be any integer from 0 to 37
If we are considering division only by positive integers
Answered by
5
100 = 3n
n = 100/3
n = 33.33333
n = 100/3
n = 33.33333
Bhavisha0506:
i am not sure
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