If 112 cm3 of h2s is mixed with 120 cm3 of Cl2 at stp, what is the mass of the
sulphur formed
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22.4 L of H₂S and Cl₂ produces 32 g of S
1 cm³= 0.001 L
112 cm³ of H₂S = 0.112L of H₂S
120 cm³ of Cl₂= 0.120 L of Cl₂
so, 0.112 L of H₂S will produce = 32/ 22.4 x 0.112
= 0.16 g of S
1 cm³= 0.001 L
112 cm³ of H₂S = 0.112L of H₂S
120 cm³ of Cl₂= 0.120 L of Cl₂
so, 0.112 L of H₂S will produce = 32/ 22.4 x 0.112
= 0.16 g of S
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