If 11200 ml of water vapour when condenses to water at ntp
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22.4 litre of will be occupied by 1 mol of water vapour at NTP.The volume occupied by a gas at NTP is 24.07 litres
Molar mass of 1 mol of water vapour = 18gm
NOW,
mass of 1 mole of water vapour = mass of 1 mol of water
given
density = 1g/ml
volume = mass/density
= 18g/1g/ml
= 18ml
so 18 ml is the answer
THANK YOU22.4 litre of will be occupied by 1 mol of water vapour at NTP.The volume occupied by a gas at NTP is 24.07 litres
Molar mass of 1 mol of water vapour = 18gm
NOW,
mass of 1 mole of water vapour = mass of 1 mol of water
given
density = 1g/ml
volume = mass/density
= 18g/1g/ml
= 18ml
so 18 ml is the answer
THANK YOU
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