Question

If 12.4eV energy is required to ionize the
hydrogen atom, then energy required to
remove an electron from n = 2 are:
a) 3.1eV
c) 10.4eV
b) 6.2eV
d) OeV​

Answer 1

Given :

The energy required to ionize hydrogen atom = 12.4 ev

To Find :

The energy required to  remove an electron from n = 2

Solution :

∵ Energy required to librate second energy = $E_1$  = 12.4 ev

∵ Ionization energy = $E_i_o_n$ = Z² Rhc

                                           = Z² × Rhc

And For hydrogen Z = 1

The value of Rhc = 13.6 ev

∴ Energy required to librate second energy = $E_2$ =  (1)² × 13.6 ev

i.e                                                                         $E_2$ = 13.6 ev

Energy required to librate both electron from hydrogen = $E_1 + E_2$

                                                                                             = 12.4 ev + 13.6 ev

                                                                                              = 26 ev

Hence, The Energy required to librate both electron from hydrogen is 26 ev   Answer