Question

If 13sinA=12 find 1/cos²A - tan²A​

Answer 1

Answer:

13sinA =12

SinA =12/13

We know that,

Sin ² A + Cos ²A = 1

(12/13)²+ Cos ²A = 1

Cos²A = 1 - 144/169

Cos²A = 25/169

Cos A = 5/13

TanA =SinA /CosA = 12/5

1/cos²A - tan²A

=1 /(5/13)² - (12/5)²

=1/(25/169) - (144/25)

=(169/25) - (144/25)

=(169-144)/25

=25/25

=1

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