Math, asked by akashwagh14, 11 months ago

if 15x+12y=9;12x+15y=6 find x-y=?​

Answers

Answered by Anonymous
56

\red {\huge {\underline{ \frak{Your \: answEr : }}}}

 \blacksquare 15x + 12y = 9 (¡)

 \blacksquare 12x + 15y = 6 (¡¡)

Multiplying (¡) with 4 and (¡¡) with 5 .

 \longrightarrow 60x + 48y = 36

 \longrightarrow 60x + 75y = 30

⠀⠀⠀- ⠀⠀⠀ - ⠀⠀ -

______________________________

 \longrightarrow -27y = 6

 \large{\longrightarrow \tt{y =  \frac{ -6}{27} }}

  \blue{\large \longrightarrow \tt{y =   \frac{ - 2}{9}  }}

Putting Value of y in (¡)

 \longrightarrow 15x + 12y = 9

\longrightarrow \tt{15x + 12 \times  \frac{ - 2}{9}  = 9}

\longrightarrow \tt{15x + 4 \times  \frac{ - 2}{3}  = 9}

\longrightarrow \tt{45x - 8 = 27}

\longrightarrow \tt{45x = 35}

 \large\longrightarrow  \tt{x =  \frac{35}{45} }

 \blue {\large\longrightarrow \tt{x =  \frac{7}{9} }}

━━━━━━━━━━━━━━━━━━━━━

  \large\tt \star \: {(x - y)}

 \large\tt \star \:{ (\frac{ - 2}{9} -  \frac{7}{9} ) }

 \large\tt \star \:{( \frac{ - 2 - 7}{9}) }

 \large\tt \star \:{ \frac{ - 9}{9} }

  \pink{\huge\tt \star   \: \boxed{\:{ - 1}}}

\huge{\red{\ddot{\smile}}}

Similar questions