Question

What is the value of (cos? 67º – sin? 23º)?​

Answer 1

Answer:

>>cos67° - sin23°

=cos(90°-23°) - sin23° {cos(90-theta)=sin theta}

=sin23° - sin23°

= 0

HOPE IT HEPLS✌✌

Answer 2

$= \cos(67) - \sin(23)$

$= \cos(67) - \cos(90 - 23)$

$= \cos(67) - \cos(67)$

WKT,

sin= cos(90°-theta )

$= 0$