If 16a + 16b = 48.what is the average of a and b ?
Answers
Answered by
64
Hi ,
Average of a and b = ( a + b ) /2 --( 1 )
16a + 16b = 48 [ given ]
Divide each term with 16 , we get
a + b = 3
Now ,
( a + b ) / 2 = 3/2
Therefore , average of a and b
= ( a + b ) /2 = 3/2
I hope this helps you.
:)
Average of a and b = ( a + b ) /2 --( 1 )
16a + 16b = 48 [ given ]
Divide each term with 16 , we get
a + b = 3
Now ,
( a + b ) / 2 = 3/2
Therefore , average of a and b
= ( a + b ) /2 = 3/2
I hope this helps you.
:)
Answered by
31
Answer:
1.5
Step-by-step explanation:
divide the eqn by 16
a+b = 3
avg =(a+b)/2
=3/2
=1.5
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