Question

If 16a + 16b = 48.what is the average of a and b ?

Answer 1

Hi ,

Average of a and b = ( a + b ) /2 --( 1 )


16a + 16b = 48 [ given ]

Divide each term with 16 , we get

a + b = 3

Now ,

( a + b ) / 2 = 3/2

Therefore , average of a and b

= ( a + b ) /2 = 3/2

I hope this helps you.

:)

Answer 2

Answer:

1.5

Step-by-step explanation:

divide the eqn  by 16

a+b = 3

avg  =(a+b)/2

        =3/2

        =1.5