Math, asked by priyaranjansir112, 11 months ago

if 18 men can do a workin 8 days, how many men are required to the work in 12 days​

Answers

Answered by systemboss
9

Answer:

12 men work in 12 days.

Step-by-step explanation:

m1 \times d1 = m2 \times d2

m1 = 18

d1 = 8

d2 = 12

m2 =  \frac{m1 \times d1}{d2}  \\  \:  \:  =  \frac{18 \times 8}{12}  \\  \:  \:  = 12

Answered by laltubudbud
1

Answer:

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