If 1g - atom of atomic nitrogen,3g molecules of dinitrogen and 6 mole of ammonia are mixed in vessel,then total number of nitrogen atoms present in the vessel are?
A) 12 Na
B) 14 Na
C) 13 Na
D) 16 Na
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1 g atom means molar mass of that element
And we know that molar mass is equivalent to the Avagadro no of particles(Na)
Now ...1 g atom of Nitrogen = 1 moles of N = 1Na
3 g molecules of N2 = 3 moles of N2= 6 moles of N = 6Na
6 mole of ammonia = 6 moles of NH3 = 6 moles of N = 6Na
Total no. of N present in the vessel is 1Na + 6Na + 6Na = 13Na
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And we know that molar mass is equivalent to the Avagadro no of particles(Na)
Now ...1 g atom of Nitrogen = 1 moles of N = 1Na
3 g molecules of N2 = 3 moles of N2= 6 moles of N = 6Na
6 mole of ammonia = 6 moles of NH3 = 6 moles of N = 6Na
Total no. of N present in the vessel is 1Na + 6Na + 6Na = 13Na
Hope it will be helpful....u can ask more questions of the FT2 which u were not able to solve!
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