Question

If 1gram of sulphur dioxide contains x molecules. How many molecules will be present in 1 Gram of oxygen

Answer 1

I hope u can understand

Answer 2

1 mole of SO2 = 64g of SO2= 6.022×1023 molecules of SO2

1g of SO2= (6.022×1023)/64 = x molecules of SO2 (given)                                                                                                      .......equation(i)

Now,

32g of O2=6.022×1023 molecules of O2

1g of O2=(6.022×1023)/32 molecules of O2

             OR

             =[(6.022×1023)/64]×2

             = (x)*2                                                              .....from equation(ii)

Hence 1g of O2 has = 2x molecules of O