Question

If 1st number 20% greater then 2nd number then 2nd number is how many percent less than 1st number

Answer 1

The answer for your question is 25%.

Hope it helps you.

Mark me as the brainliest please.

Answer 2

let the first number be x

second number be y

given x =y + 20y/100

x =(100y +20y )/100

x=120y/100

x=1.2y

the two numbers are 1.2y , y

let 1.2y:y =100: k

k:100=1:1.2

k=100/1.2 =1000/12=250/3=83.33%

loss =100-83.33

=16.67