Question

If 2ⁿ¹⁻ⁿ² = 16 and 2ⁿ¹⁺ⁿ² =64, then value of n₁ and n₂

Answer 1

Answer:

If 2ⁿ¹⁻ⁿ² = 16 and 2ⁿ¹⁺ⁿ² =64, then value of n₁ and

Answer 2

Step-by-step explanation:

$2^{n1-n2} = 16\\n1-n2=8$

$2^{n1-n2} =64\\n1-n2=32$

now:

$n1-n2=32\\n1+n2=8\\n1=24\\so \\24+n2=8\\n2=-16$

here -ve sign will not be considered valid so

$n2=16$