Question

If √2+ 3 = 16, then the value of is equal to​

Answer 1

$\sqrt{2}^{x-3} = 16 \\ \\ squaring \: both \: sides, \\ {2}^{x - 3} = 256 = {2}^{x - 3} = {2}^{8} \\ \\ x - 3 = 8 \\ \\so \: ..11</p><p></p><p>$