Question

if 2 and (-3) are the zeros of the quadratic polynomial x^2+(a+1)x+b find the valuez of a and b​

Answer 1

Answer:

the answer is

a = 0 and b = -6

Step-by-step explanation:

p(x) = x^2+(a+1)x+b

2 is the zero of this polynomial,

p(2) = 2^2+(a+1)(2)+b = 0

4+2a+2+b = 0

2a+b+6 = 0

b+6 = -2a —(1)

-3 is the zero of given polynomial,

p(-3) = (-3)^2+(a+1)(-3)+b = 0

9-3a-3+b = 0

-3a+b+6 = 0

b+6 = 3a —(2)

equating (1) and (2),

-2a = 3a

5a = 0

a = 0

a = 0 b = -6