If 2 angle A=3 angle B =6 angle
C of a triangle in a ∆ABC.find all angles of the triangle
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Answer:
Given: 2<A=3<B=6<c
then,
2<A=6<c
=> <A=6÷2<c
=> <A=3<c
3<B=6<C
=> <B = 6÷3<C
=> <B=2<C
Hence,
<A+<B+<C=180° (Angle sum Property)
= 3<C+2<C+<C=180°
=6<C=180°
=<C=180°÷6=30°
Then,
<A=3<C=3×30°=90°
<B=2<C=2×30°=60°.
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