If 2 dice are rolled simultaneously what is the probability of getting sum of 2 numbers on it is 7 ?
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S=((1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
n(s)=36
event A= getting sum of the dices 7
A= (1,6)(2,5)(3,4)(4,3)(5,2)(6,1)
n(a)= 6
p(a)=n(a)/n(s)
=6/36
=1/6
∴ The probability of getting sum as 7 when two dice are thrown is 1/6.
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