if 2 is a root of the eqation x^2+kx+q=0 has equal roots, find the value of k
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since eqn has. 2. equal roots... therefore the eqn will be perfect square with roots =2,2
the eqn will be
(x-2)^2=0
I. e., x^2 +4x-4=0
compare with x^2+kx+q=0
u get
k=4,,,q=-4
the eqn will be
(x-2)^2=0
I. e., x^2 +4x-4=0
compare with x^2+kx+q=0
u get
k=4,,,q=-4
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