Question

If 2 is a root of the equation x^2+kx+12=0 then find value of k

Answer 1

$p(x) = {x}^{2} + kx + 12 \\ p(2) = {2}^{2} + 2k + 12 = 0 \\ 4 + 2k = - 12 \\ 2k = - 16 \\ k = - 8$

hence the value of k is -8

hope it helps you

#puja

Answer 2

If hope it will help you

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