Question

If -2 is a zero of ax²-3(a-1) x- 4 Then find the value of a.
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Answer 1

Answer:

a = 1, if -2 is the zero of ax² - 3(a - 1)x - 4.

Step-by-step explanation:

Let p(x) = ax² - 3(a - 1)x - 4

We have x = -2

then,

p(-2) must be 0, because we know that, x = -2 is a solution.

p(-2) = a(-2)² - 3(a - 1)(-2) - 4

0 = 4a + 6a - 6 - 4

10a - 10 = 0

10(a - 1) = 0

a - 1 = 0/10

a - 1 = 0

a = 1

Hence,

a = 1, if -2 is the zero of ax² - 3(a - 1)x - 4.

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