Question

If 2^x-2^x-1=8, then find the value of x^3 is?

Answer 1

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The given eqution is 

2x+1=31−x2x+1=31−x

Taking log base 2 on both sides 

(x+1)log2(2)=(1−x)log2(3)(x+1)log2⁡(2)=(1−x)log2⁡(3)

x+1=log2(3)−x.log2(3)x+1=log2⁡(3)−x.log2⁡(3)

x(1+log2(3))=log2(3)−1x(1+log2⁡(3))=log2(3)−1


x=log2(3)−11+log2(3)