Question

If (2^x)(3^y) = 288, where x and y are positive integers, then [2^(x - 1)][3^(y - 2)] =

Answer 1

Answer:

48

Step-by-step explanation:

2^x/2 = 2^(x-1)

3^y/3=3^(y-1)

Therefore, 2^(x-1)*3^(y-1)= (2^x/2)*(3^y/2)

                                       = (2^x*3^y)/6

                                       = 288/6 = 48

Plz mark as brainliest!!!!!