If 2^x+y=2^x-y=√8 find the value of x and y
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Step-by-step explanation:
2^(x+y) = 2(x-y) =_/8
2^(x+y) = 2(x-y) = (2_/2 = 2×2^1/2 = 2(2^1/2))
therefore, x+y = x-y = 1/2 ( when bases are same, powers are equated)
x will get cancelled on both sides, remaining
y = -y = 1/2
so, y = 1/2 and x = 0
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