Question

if 200 ml of 0.1 M H2SO4 solution is mixed with 200 ml of 0.15M NaOH solution then heat evolve during the neutralisation process is

Answer 1

Let the volume of H2SO4 added be X ml.

Final molarity has to be 0.05 and volume will be (from NaOH)50+X(from H2SO4).

Now Subtracting the product of molarity of NaOH and its volume from the same of H2SO4

(for H2SO4 the product of volume and molarity)x*0.1-50*0.1(for H2SO4 the product of volume and molarity)

This gives the product of volume and molarity of unreacted acid.

Now equate this with (50+X)*0.05

(50+X)*0.05=X*0.1-50*0.1

5/2+0.05X=0.1X-5

0.05X=7.5

Thus

X=150ml.

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Answer 2

Explanation:

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