bill and amy want to ride their bikes from their bikes from their neighbourhood school which is 14.4 km away . it takes amy 40 minutes to arrive at school. Bill arrives 20 mins after amy . how much faster in meters/ second Amy's average speed for the entire trip?
Answers
Answer:
amy-
speed = distance/time
= 14.4/40
= 3.6m/s
bill-
speed = distance/time
= 14.4/60
= 2.4m/s
amy is 1.2 seconds faster than bill.
hope this helps!! <3
Step-by-step explanation:
Amy's average speed for the entire trip is 2/3 m/s faster than Bill.
Given:
Bill and Amy want to ride their bikes from their bikes from their neighborhood school which is 14.4 km away.
It takes Amy 40 minutes to arrive at school.
Bill arrives 20 mins after Amy.
To find:
How faster in m/s Amy's average speed for the entire trip
Solution:
Assuming that both Bill and Amy leave at the same time.
The distance from their neighborhood to school = 14.4km
Time taken by Amy to arrive at school = 40mins
Bill arrives 20 mins after Amy reaches school.
Bill:
d = 14.4 km = 14400 meters
t = 40min + 20min = 60minutes
60 minutes = 60*60 = 3600 seconds
V = 14400 / 3600 = 4m/s
Amy:
d = 14.4 km = 14400 meters
t = 40 minutes
40 minutes = 40*60 = 2400 seconds
V = 14400 / 2400 = 6m/s
Comparing the speed of Bill and Amy we get,
≅ 4/6 = 2/3 meters per second
∴ Amy's average speed for the entire trip is m/s faster than Bill.
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