Volume of 0.1gm mole of So^2 at stp
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molar mass of so^2=64gm
and mass given =0.1 gm
therefore no.of moles moles so^2=0.1/64
now volume at s.t.p is.
0.1/64*22.4L
which is = 0.035L
and mass given =0.1 gm
therefore no.of moles moles so^2=0.1/64
now volume at s.t.p is.
0.1/64*22.4L
which is = 0.035L
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