Question

if 2cosA+sinA-2=0 if 0<A<90then the value of A is​

Answer 1

Answer:

Given

sinA+cosA=

2

sin(90−A)

⇒

2

1

sinA+

2

1

cosA=sin(90−A)

⇒sinA.cos45

∘

+cosA+sin45

∘

=sin(90−A)

⇒(A+45

∘

)=sin(90

∘

−A)

Equating

A+45=90−A

⇒2A=45

∘

⇒A=22

2

1

∘

A=

8

π

∴cotA=cot

8

π

=

2

+1

solution

Expand-image

Answer 2

Answer:

As long as we are dealing with ‘real’ values of theta, then:

maximum value is 1, which occurs when theta is 90° (and any multiple of 360° more or less than this)

minimum value is -1, which occurs when theta is 270° (and any multiple of 360° more or less than this)