If 2gram of naoh is present in 200ml of its solution its molarity
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We know that molarity Is given by
M = moles of solvent / volume of solution
Here given mass of NaOH = 2 gram
molar mass of NaOH = 40 g
Thus no of moles of NaOH = 2/40 => 1/20 moles
Now molarity =
=> 1
HENCE MOLARITY OF THE SOLUTION IS 1 M
M = moles of solvent / volume of solution
Here given mass of NaOH = 2 gram
molar mass of NaOH = 40 g
Thus no of moles of NaOH = 2/40 => 1/20 moles
Now molarity =
=> 1
HENCE MOLARITY OF THE SOLUTION IS 1 M
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