If (2x-3y)=3 and xy=9,find the value of (8x^3-27y^3)
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(8x3 - 27 y3)
(2x)3 -(3y)3
(2x-3y)3 +3 xy(x+y)
(3)3 +3(9)(x+y)
27 +27(x+y)
27[1+x+y]
(2x)3 -(3y)3
(2x-3y)3 +3 xy(x+y)
(3)3 +3(9)(x+y)
27 +27(x+y)
27[1+x+y]
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