Question

if (2x-y)^2 + (3x+y-25)^2 =0 , then find the value of (x^2 + y^2)​

Answer 1

$(2x - y) {}^{2} + {(3x + y - 25)}^{2} = 0 \\ {(4x }^{2} + {y}^{2} - 4xy) + (9x {}^{2} + y {}^{2} + 625 + 2(3x)(y) - 2(y)(25) - 2(25)(3x) = 0 \\ 4x { }^{2} + y {}^{2} - 4xy + 9x {}^{2} + y {}^{2} + 625 + 6xy - 50y - 150x = 0 \\ 13x {}^{2} + 2y {}^{2} + 2xy + 625 = 150x + 50y$