if √3+√2=x,then √3-√2 will be?
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x = root 3 + root2
1/x = 1/root3 + root2
rationalise with root3 - root2
1/x = root3 - root2/ (root3) ^2 - (root2) ^2
1/x = root3 - root2 / 3 -2
1/x = root3 - root2/1
1/x = root3 - root2
1/x is answer for root3 - root2
1/x = 1/root3 + root2
rationalise with root3 - root2
1/x = root3 - root2/ (root3) ^2 - (root2) ^2
1/x = root3 - root2 / 3 -2
1/x = root3 - root2/1
1/x = root3 - root2
1/x is answer for root3 - root2
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